Trắc nghiệm Đại số và Giải tích 11 Bài 4 (Có đáp án): Vi phân

A. dy= xcosxdx

B. dy= xcosx

C. dy= (2sinx + xcosx)dx

D. dy= (sinx+cosx)dx

A. $dy=\frac{2\tan \sqrt{x^2+1}}{{\cos }^2\sqrt{x^2+1}}dx$

B. $dy=\frac{2x\tan \sqrt{x^2+1}}{\sqrt{x^2+1}{\sin }^2\sqrt{x^2+1}}dx$

C. $dy=\frac{2x\tan \sqrt{x^2+1}}{\sqrt{x^2+1}{\cos }^2\sqrt{x^2+1}}dx$

D. $dy=\frac{2\tan \sqrt{x^2+1}}{\sqrt{x^2+1}{\sin }^2\sqrt{x^2+1}}dx$

A. $dy=-{\sin }^2(1-x)dx$

B. $dy=3{\cos }^2(1-x).\sin (1-x)dx$

C. $dy=-3{\cos }^2(1-x)\sin (1-x)dx$

D. $dy=3{\cos }^2(1-x)dx$

A. ∆f(1)=0,11;df(1)=0,2

B. ∆f(1)=0,11;df(1)=0,1

C. ∆f(1)=0,2;df(1)=0,11

D. ∆f(1)=0,2;df(1)=0,1

A. $dy=10{(2x+1)}^4$

B. $dy=5{(2x+1)}^{4}dx$

C. $dy={(2x+1)}^{4}dx$

D. $dy=10{(2x+1)}^{4}dx$

A. $dy=-{\sin }^2(1-x)dx$

B. $dy=3{\cos }^2(1-x).\sin (1-x)dx$

C. $dy=-3{\cos }^2(1-x)\sin (1-x)dx$

D. $dy=3{\cos }^2(1-x)dx$

A. $dy=\frac{1}{7}dx$

B. $dy=7dx$

C. $dy=-\frac{1}{7}dx$

D. $dy=-7dx$

A. 9

B. -9

C. 90

D. -90

A. -0,02

B. 0,01

C. 0,4

D.  -0,06

A. $\frac{\sqrt{2}}{2}+\frac{\pi }{180}$

B. $\frac{1}{2}+\frac{\sqrt{2}\pi }{240}$

C. $\frac{\sqrt{2}}{2}+\frac{\sqrt{2}\pi }{360}$

D. Đáp án khác

A. 1,0004

B. 1,0035

C. 1,00037

D.1,0005

A. $\text{d}y=\frac{2\sqrt{x}}{4x\sqrt{x}{\cos }^2\sqrt{x}}\text{d}x$

B. $\text{d}y=\frac{\sin \left(2\sqrt{x}\right)}{4x\sqrt{x}{\cos }^2\sqrt{x}}\text{d}x$

C. $\text{d}y=\frac{2\sqrt{x}-\sin \left(2\sqrt{x}\right)}{4x\sqrt{x}{\cos }^2\sqrt{x}}\text{d}x$

D. $\text{d}y=-\frac{2\sqrt{x}-\sin \left(2\sqrt{x}\right)}{4x\sqrt{x}{\cos }^2\sqrt{x}}\text{d}x$