Trắc nghiệm Vi phân có đáp án (Phần 2)

A. $\text{d}y=2\left(x-1\right)\text{d}x$

B. $\text{d}y={\left(x-1\right)}^2\text{d}x$

C. $\text{d}y=2\left(x-1\right)$

D. $\text{d}y=2\left(x-1\right)\text{d}x$

A. $dy=(1+{\tan }^{2}2x)dx$

B. $dy=(1-{\tan }^{2}2x)dx$

C. $dy=2(1-{\tan }^{2}2x)dx$

D. $dy=2(1+{\tan }^{2}2x)dx$

A. $\text{d}f\left(x\right)=\frac{-\sin 4x}{2\sqrt{1+{\cos }^{2}2x}}\text{d}x$

B. $\text{d}f\left(x\right)=\frac{-\sin 4x}{\sqrt{1+{\cos }^{2}2x}}\text{d}x$

C. $\text{d}f\left(x\right)=\frac{\cos 2x}{\sqrt{1+{\cos }^{2}2x}}\text{d}x$

D. $\text{d}f\left(x\right)=\frac{-\sin 2x}{2\sqrt{1+{\cos }^{2}2x}}\text{d}x$

A. $\text{d}y=\frac{\text{d}x}{{\left(x-1\right)}^2}$

B. $\text{d}y=\frac{3\text{d}x}{{\left(x-1\right)}^2}$

C. $\text{d}y=\frac{-3\text{d}x}{{\left(x-1\right)}^2}$

D. $\text{d}y=-\frac{\text{d}x}{{\left(x-1\right)}^2}$

A. $\text{d}y=\left(x\cos x–\sin x\right)\text{d}x$

B. $\text{d}y=\left(x\cos x\right)\text{d}x$

C. $\text{d}y=\left(\cos x–\sin x\right)\text{d}x$

D. $\text{d}y=\left(x\sin x\right)\text{d}x$

A. - 4

B. 11

C. 1,1

D. -0,4

A. 4,0313

B. 4,0312

C. 4,0311

D. 4,0314

A. $\frac{\sqrt{3}}{3}-\frac{\pi }{1200}$

B. $\frac{\sqrt{3}}{2}-\frac{\pi }{1440}$

C. $\frac{\sqrt{3}}{2}+\frac{\pi }{140}$

D. $\frac{\sqrt{3}}{3}+\frac{\pi }{100}$

A. $dy=(3x^2-4x)dx$

B. $dy=(3x^2+x)dx$

C. $dy=(3x^2+2x)dx$

D. $dy=(3x^2+4x)dx$

A. $dy=\frac{3}{2\sqrt{3x+2}}dx$

B. $dy=\frac{1}{2\sqrt{3x+2}}dx$

C. $dy=\frac{1}{\sqrt{3x+2}}dx$

D. $dy=\frac{3}{\sqrt{3x+2}}dx$

A. $dy=\left(\cos 2x+3{\sin }^{2}x\cos x\right)dx$

B. $dy=\left(2\cos 2x+3{\sin }^{2}x\cos x\right)dx$

C. $dy=\left(2\cos 2x+{\sin }^{2}x\cos x\right)dx$

D. $dy=\left(\cos 2x+{\sin }^{2}x\cos x\right)dx$

A. $\text{d}y=-\frac{x^2-2x-2}{{(x-1)}^2}\text{d}x$

B. $\text{d}y=\frac{2x+1}{{(x-1)}^2}\text{d}x$

C. $\text{d}y=-\frac{2x+1}{{(x-1)}^2}\text{d}x$

D. $\text{d}y=\frac{x^2-2x-2}{{(x-1)}^2}\text{d}x$