Trắc nghiệm Toán 9 Bài 4 (có đáp án): Một số hệ thức về cạnh và góc trong tam giác vuông (phần 2)

A . MN = MP. sin P

B . MN = MP. cos P

C . MN = MP. tan P

D . MN = MP. cot P

A . NP = MP. sin P

B . NP = MN. cot P

C . NP = MN. tan P

D . NP = MP. cot P

A . b = a.sin B = a.cos C

B . a = c.tan B = c.cot C

C . $a^2=b^2+c^2$

D . c = a.sin C = a.cos B

A . b = c.sin ${50}^0$ .

B . b = a.tan ${50}^0$ .

C . b = c.cot ${50}^0$ .

D . c = b.cot ${50}^0$ .

A . AB = $\frac{5\sqrt{3}}{3}$ ; BC = $\frac{20\sqrt{3}}{3}$

B . AB = $\frac{10\sqrt{3}}{3}$ ; BC = $\frac{14\sqrt{3}}{3}$

C . AB = $\frac{10\sqrt{3}}{3}$ ; BC = 20 $\sqrt{3}$

D . AB = $\frac{10\sqrt{3}}{3}$ ; BC = $\frac{20\sqrt{3}}{3}$

A . AB = 20 $\sqrt{3}$ ; BC = 40

B . AB = 20 $\sqrt{3}$ ; BC = 40 $\sqrt{3}$

C . AB = 20; BC = 40

D . AB = 20; BC = 20 $\sqrt{3}$

A . $AC\approx 7,71;\hat{C}={40}^0$

B . $AC\approx 7,72;\hat{C}={50}^0$

C . $AC\approx 7,71;\hat{C}={50}^0$

D . $AC\approx 7,73;\hat{C}={50}^0$

A . $AC\approx 12,29;\hat{C}={45}^0$

B . $AC\approx 12,29;\hat{C}={35}^0$

C . $AC\approx 12,2;\hat{C}={35}^0$

D . $AC\approx 12,92;\hat{C}={40}^0$

A . AC = 8 (cm); $\hat{B}\approx {36}^{0}52\text{'}$

B . AC = 9 (cm); $\hat{B}\approx {36}^{0}52\text{'}$

C . AC = 9 (cm); $\hat{B}\approx {37}^{0}52\text{'}$

D . AC = 9 (cm); $\hat{B}\approx {36}^{0}55\text{'}$

A . $BC=\sqrt{74}\left(cm\right);\hat{C}\approx {35}^{0}32\text{'}$

B . $BC=\sqrt{74}\left(cm\right);\hat{C}\approx {36}^{0}32\text{'}$

C . $BC=\sqrt{74}\left(cm\right);\hat{C}\approx {35}^{0}33\text{'}$

D . $BC=\sqrt{74}\left(cm\right);\hat{B}\approx {35}^{0}32\text{'}$

A . AC = 22; $\hat{B}\approx {67}^0$

B . AC = 24; $\hat{B}\approx {66}^0$

C . AC = 24; $\hat{B}\approx {67}^0$

D . AC = 24; $\hat{B}\approx {68}^0$

A . BC = 10

B . BC = 11

C . BC = 9

D . BC = 12

A . BC = $3\sqrt{3}+6$

B . BC = $3\sqrt{13}+6$

C . BC = 9

D . BC = 6

A . 4

B . 5

C . 7

D .8

A . 4

B . 5

C . 6

D . 8

A . 17,36 $c{m}^2$

B . 17,4 $c{m}^2$

C . 17,58 $c{m}^2$

D . 17,54 $c{m}^2$ .

A . 60 $c{m}^2$ .

B . 80 $c{m}^2$ .

C . 40 $c{m}^2$ .

D . 160 $c{m}^2$ .

A . $\hat{A}={50}^0$ ; $\hat{C}={65}^0$ ; AB = AC = 5,6; BC = 8,52

B . $\hat{A}={50}^0$ ; $\hat{C}={65}^0$ ; AB = AC = 5,6; BC = 4,42

C . $\hat{A}={50}^0$ ; $\hat{C}={65}^0$ ; AB = AC = 4,7; BC = 4,24

D . $\hat{A}={50}^0$ ; $\hat{C}={65}^0$ ; AB = AC = 4,7; BC = 3,97

A . $\hat{B}={53}^{0}8\text{'}$ ; $\hat{C}={36}^{0}52\text{'}$

B . $\hat{B}={36}^{0}52\text{'}$ ; $\hat{C}={53}^{0}8\text{'}$

C . $\hat{B}={48}^{0}35\text{'}$ ; $\hat{C}={41}^{0}25\text{'}$

D . $\hat{B}={41}^{0}25\text{'}$ ; $\hat{C}={48}^{0}35\text{'}$

A . $\hat{A}={45}^0$ ; $\hat{B}=\hat{C}={67}^{0}30\text{'}$

B . $\hat{A}={30}^0$ ; $\hat{B}=\hat{C}={75}^0$

C . $\hat{A}={48}^{0}6\text{'}$ ; $\hat{B}=\hat{C}={65}^{0}57\text{'}$

D . $\hat{A}={53}^{0}8\text{'}$ ; $\hat{B}=\hat{C}={63}^{0}26\text{'}$

A . $AD=a.\cos 22,5^0$ ; $DC=a-a.\cos 22,5^0$ .

B . $AD=a.\sin 22,5^0$ ; $DC=a-a.\sin 22,5^0$ .

C . $AD=a.\tan 22,5^0$ ; $DC=a-a.\tan 22,5^0$ .

D . $AD=a.\mathrm{co}t22,5^0$ ; $DC=a-a.cot22,5^0$ .

A . $\left(\begin{array}{c}AB=2\sqrt{3}a\\ AC=2a\end{array}\right)$

B . $\left(\begin{array}{c}AB=\sqrt{3}a\\ AC=\frac{1}{2}a\end{array}\right)$

C . $\left(\begin{array}{c}AB=a\\ AC=3a\end{array}\right)$

D . $\left(\begin{array}{c}AB=\sqrt{3}a\\ AC=a\end{array}\right)$

A . $S_{ABCD}$ = 2 (đvdt)

B . $S_{ABCD}$ = 3 (đvdt)

C . $S_{ABCD}$ = 4 (đvdt)

D . $S_{ABCD}$ = $\frac{5}{2}$ (đvdt)

A . AH = 2,8 cm; $cos\widehat{ACB}=\frac{3}{5}$

B . AH = 2,4 cm; $cos\widehat{ACB}=\frac{4}{5}$

C . AH = 2,5 cm; $cos\widehat{ACB}=\frac{3}{4}$

D . AH = 1,8 cm; $cos\widehat{ACB}=\frac{2}{3}$

A . $\frac{1}{2}{a}^2\sin \alpha .\cos \alpha$

B . $a^2\sin \alpha .\cos \alpha$

C . $2a^2\sin \alpha .\cos \alpha$

D . $3a^2\sin \alpha .\cos \alpha$

A . $\alpha ={45}^0$ ; $ma{x}_{S_{ABC}}=\frac{1}{2}{a}^2$ .

B . $\alpha ={30}^0$ ; $ma{x}_{S_{ABC}}=\frac{\sqrt{3}}{4}{a}^2$ .

C . $\alpha ={60}^0$ ; $ma{x}_{S_{ABC}}=\frac{\sqrt{3}}{4}{a}^2$ .

D . $\alpha ={45}^0$ ; $ma{x}_{S_{ABC}}=\frac{1}{4}{a}^2$ .

A . EI = 4,5cm

B . EI = 5,4cm

C . EI = 5,9cm

D . EI = 5,6cm