Trắc nghiệm Toán 7 Bài 2 (có đáp án): Hai tam giác bằng nhau

A . AB = MN

B . AC = NP

C . $\hat{A}=\hat{M}$

D . $\hat{P}=\hat{C}$

A . PQ = DE

B . PR = EF

C . $\hat{Q}=\hat{E}$

D . $\hat{D}=\hat{P}$

A . $\hat{D}$ = 33 $°$

B . $\hat{D}$ = 42 $°$

C . $\hat{E}$ = 32 $°$

D . $\hat{E}$ = 66 $°$

A . $\hat{C}$ = 45 $°$

B . $\hat{B}$ = 45 $°$

C . $\hat{A}$ = 45 $°$

D . $\hat{C}$ = 90 $°$

A . $\Delta ABC=\Delta DEF$

B . $\Delta ABC=\Delta EFD$

C . $\Delta ABC=\Delta FDE$

D . $\Delta ABC=\Delta DFE$

A . $\Delta MNP$ = $\Delta IJK$

B . $\Delta MNP$ = $\Delta IKJ$

C . $\Delta MNP$ = $\Delta KIJ$

D . $\Delta MNP$ = $\Delta JKI$

A . $\hat{B}$ = $\hat{E}$ = 60 $°$

B . $\hat{B}$ = 60 $°$ ; $\hat{E}$ = 7 0 $°$

C . $\hat{B}$ = $\hat{E}$ = 78 $°$

D . $\hat{B}$ = $\hat{E}$ = 70 $°$

A . $\hat{D}$ = 80 $°$ ; $\hat{K}$ = 40 $°$

B . $\hat{D}$ = 40 $°$ ; $\hat{K}$ = 60 $°$

C . $\hat{D}$ = 60 $°$ ; $\hat{K}$ = 80 $°$

D . $\hat{D}$ = 40 $°$ ; $\hat{K}$ = 80 $°$

A . NP=BC=9cm

B . NP=BC=11cm

C . NP=BC=10cm

D . NP=9cm;BC=10cm

A . MN=AC=7cm,;BC=NP=10cm

B . MN=AC=10cm,;BC=NP=7cm

C . MN=7cm;AC=10cm,;BC=NP=7cm

D . MN=10cm;AC=7cm;BC=NP=7cm

A . 24cm

B . 20cm

C . 18 cm

D . 30 cm

A . 30cm

B . 22 cm

C . 18 cm

D . 20 cm

A . $\hat{A}$ = $\hat{D}$ = 65 $°$ , $\hat{F}$ = $\hat{C}$ = 50 $°$

B . $\hat{A}$ = $\hat{D}$ = 50 $°$ , $\hat{F}$ = $\hat{C}$ = 6 5 $°$

C . $\hat{A}$ = $\hat{D}$ = 75 $°$ , $\hat{F}$ = $\hat{C}$ = 50 $°$

D . $\hat{A}$ = $\hat{D}$ = 50 $°$ , $\hat{F}$ = $\hat{C}$ = 7 5 $°$

A . $\hat{A}$ = $\hat{D}$ = 105 $°$ , $\hat{F}$ = $\hat{C}$ = 4 0 $°$

B . $\hat{A}$ = $\hat{D}$ = 90 $°$ , $\hat{F}$ = $\hat{C}$ = 50 $°$

C . $\hat{A}$ = $\hat{D}$ = 95 $°$ , $\hat{F}$ = $\hat{C}$ = 4 0 $°$

D . $\hat{A}$ = $\hat{D}$ = 40 $°$ , $\hat{F}$ = $\hat{C}$ = 9 5 $°$

A . 4 cm

B . 6 cm

C . 8 cm

D . 10 cm