Trắc nghiệm Phương trình đường tròn có đáp án (Vận dụng)

A. $m\in R$

B. $m\in \left(-\infty ;1\right)\cup \left(2;+\infty \right)$

C. $m\in (-\infty ;1]\cup [2;+\infty )$

D. $m\in \left(-\infty ;\frac{1}{3}\right)\cup \left(2;+\infty \right)$

A. Không có

B. 6

C. 7

D. 8

A. ${\left(x-1\right)}^2+{\left(y-1\right)}^2=\sqrt{5}$

B. ${\left(x+1\right)}^2+{\left(y+1\right)}^2=\sqrt{5}$

C. ${\left(x-1\right)}^2+{\left(y-1\right)}^2=5$

D. ${\left(x+1\right)}^2+{\left(y+1\right)}^2=5$

A. $x^2+y^2-2x-y+20=0$

B. ${\left(x-2\right)}^2+{\left(y-1\right)}^2=20$

C. $x^2+y^2-4x-2y+20=0$

D. $x^2+y^2-4x-2y-20=0$

A. $x^2+y^2-\frac{83}{27}x+\frac{17}{9}y+\frac{338}{27}=0$

B. $x^2+y^2-\frac{83}{54}x+\frac{17}{18}y-\frac{338}{27}=0$

C. $x^2+y^2+\frac{83}{27}x+\frac{17}{9}y-\frac{338}{27}=0$

D. $x^2+y^2-\frac{83}{27}x+\frac{17}{9}y-\frac{338}{27}=0$

A. m=4

B. m=8

C. m=-8

D. m=-4

A. $M\left(-\frac{11}{5};\frac{23}{5}\right);N\left(\frac{1}{5};\frac{7}{5}\right)$

B. $M\left(-\frac{2}{5};\frac{11}{5}\right);N\left(\frac{1}{5};\frac{7}{5}\right)$

C. $M\left(-\frac{2}{5};\frac{11}{5}\right);N\left(1;2\right)$

D. $M\left(-\frac{11}{5};\frac{23}{5}\right);N\left(1;2\right)$

A. m=2

B. m=-1

C. m=1

D. m=-2

A. I (0; 0)

B. I (1; 0)

C. I (3; 2)

D. I (1; 1)

A. 2R

B. $R\sqrt{2}$

C. $\frac{R\sqrt{2}}{2}$

D. R

A. m = ± 3

B. m = ± 5

C. m = ± 1D

D. m = 0

A. 3x + 4y – 14 = 0

B. 3x + 4y + 36 = 0

C. 4x − 3y + 36 = 0

D. 4x − 3y + 14 = 0

A. x – y + 6 = 0

B. x – y + 3 − $\sqrt{2}$ = 0

C. x – y + 4 $\sqrt{2}$ = 0

D. x – y + 3 +3 $\sqrt{2}$ = 0

A. 0

B. 1

C. 2

D. 4

A. $M_1\left(-\sqrt{2};\sqrt{2}-1\right)hoặc{M}_1\left(\sqrt{2};-\sqrt{2}-1\right)$

B. $M_1\left(-\sqrt{2};\sqrt{2}+1\right)hoặc{M}_1\left(\sqrt{2};-\sqrt{2}+1\right)$

C. $M_1\left(\sqrt{2};\sqrt{2}+1\right)hoặc{M}_1\left(\sqrt{2};-\sqrt{2}-1\right)$

D. $M_1\left(-\sqrt{2};\sqrt{2}-1\right)hoặc{M}_1\left(\sqrt{2};\sqrt{2}+1\right)$