Trắc nghiệm Một số hệ thức về cạnh và góc trong tam giác vuông có đáp án (Vận dụng)

A. BC = 10

B. BC = 11

C. BC = 9

D. BC = 12

A. $BC=3\sqrt{3}+6$

B. $BC=3\sqrt{13}+6$

C. BC = 9

D. BC = 6

A. 4

B. 5

C. 7

D. 8

A. 4

B. 5

C. 6

D. 8

A. 17,36 cm ² .

B. 17,4 cm ²

C. 17,58 cm ²

D. 17,54 cm ²

A. 60 cm ²

B. 80 cm ²

C. 40 cm ²

D. 160 cm ²

A. $\hat{A}$ = 50 ^o ; $\hat{C}$ = 65 ^o ; AB = AC = 5,6; BC = 8,52

B. $\hat{A}$ = 50 ^o ; $\hat{C}$ = 65 ^o ; AB = AC = 5,6; BC = 4,42

C. $\hat{A}$ = 50 ^o ; $\hat{C}$ = 65 ^o ; AB = AC = 4,7; BC = 4,24

D. $\hat{A}$ = 50 ^o ; $\hat{C}$ = 65 ^o ; AB = AC = 4,7; BC = 3,97

A. $\hat{B}=53°8’;\hat{C}=36°52’$

B. $\hat{B}=36°52\text{'}’;\hat{C}=53°8\text{'}$

C. $\hat{B}=48°35\text{'};\hat{C}=41°25\text{'}$

D. $\hat{B}=41°25\text{'};\hat{C}=48°35\text{'}$

A. $\hat{A}=45°;\hat{B}=\hat{C}=67°30’$

B. $\hat{A}=30°;\hat{B}=\hat{C}=75°$

C. $\hat{A}=48°6\text{'};\hat{B}=\hat{C}=65°57’$

D. $\hat{A}=53°8\text{'};\hat{B}=\hat{C}=63°26’$

A. AD = a. cos 22,5 ^o ; DC = a – a. cos 22,5 ^o

B. AD = a. sin 22,5 ^o ; DC = a – a. sin 22,5 ^o

C. AD = a. tan 22,5 ^o ; DC = a – a. tan 22,5 ^o

D. AD = a. cot 22,5 ^o ; DC = a – a. cot 22,5 ^o

A. $\left(\begin{array}{c}AB=2\sqrt{3}a\\ AC=2a\end{array}\right)$

B. $\left(\begin{array}{c}AB=\sqrt{3}a\\ AC=\frac{1}{2}a\end{array}\right)$

C. $\left(\begin{array}{c}AB=a\\ AC=3a\end{array}\right)$

D. $\left(\begin{array}{c}AB=\sqrt{3}a\\ AC=a\end{array}\right)$

A. $S_{ABCD}=2\left(đvdt\right)$

B. $S_{ABCD}=3\left(đvdt\right)$

C. $S_{ABCD}=4\left(đvdt\right)$

D. $S_{ABCD}=\frac{5}{2}\left(đvdt\right)$

A. AH = 2,8 cm; cos $\widehat{ACB}$ = $\frac{3}{5}$

B. AH = 2,4 cm; cos $\widehat{ACB}=\frac{4}{5}$

C. AH = 2,5 cm; cos $\widehat{ACB}=\frac{3}{4}$

D. AH = 1,8 cm; cos $\widehat{ACB}=\frac{2}{3}$

A. $\frac{1}{2}{a}^2\sin \left(\alpha \right)\cos \left(\alpha \right)$

B. $a^2\sin \left(\alpha \right)\cos \left(\alpha \right)$

C. $2a^2\sin \left(\alpha \right)\cos \left(\alpha \right)$

D. $3a^2\sin \left(\alpha \right)\cos \left(\alpha \right)$

A. $\alpha =45°;ma{x}_{S_{ABC}}=\frac{1}{2}{a}^2$

B. $\alpha =30°;ma{x}_{S_{ABC}}=\frac{\sqrt{3}}{4}{a}^2$

C. $\alpha =60°;ma{x}_{S_{ABC}}=\frac{\sqrt{3}}{4}{a}^2$

D. $\alpha =45°;ma{x}_{S_{ABC}}=\frac{1}{4}{a}^2$