Trắc nghiệm Các quy tắc tính đạo hàm có đáp án (phần 2)

A. 2

B. 6

C. - 4

D. 3

A. 4

B. 14

C. 15

D. 24

A. -32

B.30

C. - 64

D. 12

A.{-1;2}

B.{-1;3}

C. {0;4}

D.{1;2}

A. 1

B. -3

C. -5

D. 0

A. 0

B. 2

C. 1

D. Không tồn tại

A. $\left(-\sqrt{3};\sqrt{3}\right)$

B. $\left(-\frac{1}{\sqrt{3}};\frac{1}{\sqrt{3}}\right)$

C. $(-\infty ;-\sqrt{3}]\cup [\sqrt{3};+\infty )$

D. $(-\infty ;-\frac{1}{\sqrt{3}}]\cup [\frac{1}{\sqrt{3}};+\infty )$

A. $m\le \sqrt{2}$

B. $m\le 2$

C. $m\le 0$

D. m<0

A. y'(1)= -4

B. y'(1)= -3

C. y'(1)= -2

D. y'(1)= -5

A. $y^{\text{'}}=2016{{(x^3-2x^2)}^2}^{015}.$

B. $y^{\text{'}}=2016{(x^3-2x^2)}^{2015}(3x^2-4x).$

C. $y^{\text{'}}=2016(x^3-2x^2)(3x^2-4x).$

D. $y^{\text{'}}=2016(x^3-2x^2)(3x^2-2x).$

A. $\frac{-3}{{\left(x+2\right)}^2}$

B. $\frac{3}{\left(x+2\right)}$

C. $\frac{3}{{\left(x+2\right)}^2}$

D. $\frac{2}{{\left(x+2\right)}^2}$

A. $-1-\frac{3}{{\left(x-2\right)}^2}$

B. $1+\frac{3}{{\left(x-2\right)}^2}$

C. $-1+\frac{3}{{\left(x-2\right)}^2}$

D. $1-\frac{3}{{\left(x-2\right)}^2}$

A. $\frac{-3x^2-13x-10}{{\left(x^2+3\right)}^2}$

B. $\frac{-x^2+x+3}{{\left(x^2+3\right)}^2}$

C. $\frac{-x^2+2x+3}{{\left(x^2+3\right)}^2}$

D. $\frac{-7x^2-13x-10}{{\left(x^2+3\right)}^2}$

A. $\frac{3x-1}{\sqrt{3x^2-2x+1}}$

B. $\frac{6x-2}{\sqrt{3x^2-2x+1}}$

C. $\frac{3x^2-1}{\sqrt{3x^2-2x+1}}$

D. $\frac{1}{2\sqrt{3x^2-2x+1}}$

A. $y\text{'}=\frac{2x-2}{\sqrt{x^2-2x}}$

B. $y\text{'}=\frac{3x^2-4}{\sqrt{x^2-2x}}$

C. $y\text{'}=\frac{2x^2-3x}{\sqrt{x^2-2x}}$

D. $y\text{'}=\frac{2x^2-2x-1}{\sqrt{x^2-2x}}$

A. $x\in \left(-\infty ;1\right)\cup \left(3;+\text{}\infty \right)$

B. $x\in \left(-\infty ;0\right)\cup \left(1;+\text{}\infty \right)$

C. $x\in \left(0;3\right)$

D. $x\in \left(0;1\right)\cup \left(1;3\right)$

A. $\frac{-x}{\left(x^2+2\right)\sqrt{x^2+2}}$

B. $\frac{x+8}{\left(x^2+2\right)\sqrt{x^2+2}}$

C. $\frac{-x-8}{\left(x^2+2\right)\sqrt{x^2+2}}$

D. $\frac{-x+8}{\left(x^2+2\right)\sqrt{x^2+2}}$

A. $\text{}S=\left(0;1\right)$

B. $\text{}S=\left(0;-1\right)$

C. $\text{}S=\left(1;-1\right)$

D. $\text{}S=\left(-1;0;1\right)$

A. $-\frac{9{\left(2x+1\right)}^2}{{\left(x-1\right)}^4}$

B. $\frac{3{\left(2x+1\right)}^2}{{\left(x-1\right)}^5}$

C. $\frac{3{\left(3x+1\right)}^2}{{\left(x-1\right)}^4}$

D. $\frac{2{\left(x+1\right)}^2}{{\left(x-1\right)}^6}$

A. $-\frac{1}{{\left(x^2-x+1\right)}^{10}}$

B. $\frac{5\left(2x-1\right)}{{\left(x^2-x+1\right)}^{10}}$

C. $-\frac{5\left(2x-1\right)}{{\left(x^2-x+1\right)}^6}$

D. $-\frac{5\left(2x-1\right)}{{\left(x^2-x+1\right)}^{10}}$

A. $\frac{2-2x}{\sqrt{1+2x-x^2}}$

B. $\frac{1-x}{\sqrt{1+2x-x^2}}$

C. $\frac{1-x}{2\sqrt{1+2x-x^2}}$

D. $\frac{1}{2\sqrt{1+2x-x^2}}$

A. $\frac{1}{2\sqrt{\frac{x^2+1}{x}}}\left(1-\frac{1}{x^2}\right)$

B. $\frac{1}{\sqrt{\frac{x^2+1}{x}}}\left(1+\frac{1}{x^2}\right)$

C. $\frac{2}{\sqrt{\frac{x^2+1}{x}}}\left(x+\frac{1}{x^2}\right)$

D. Đáp án khác

A. $\frac{3-x}{\sqrt{1-x}\left(1-x\right)}.$

B. $\frac{2(3-x)}{\sqrt{1-x}\left(1-x\right)}.$

C. $\frac{3-x}{2\sqrt{1-x}\left(1-x\right)}.$

D. $\frac{3-x}{2\left(1-x\right)}.$

A. $\frac{3}{2}\sqrt{x-2}$

B. $\frac{3}{4}\sqrt{x-2}.(x-2)$

C. $\frac{3}{4}(x-2)$

D. $\frac{3}{4}\sqrt{x-2}.{(x-2)}^2$

A. $x\in \left(0;1\right)$

B. $x\in \left(-1;0\right)$

C. $x\in \left(-\infty ;0\right)\cup \left(1;+\infty \right)$

D. $x\in \left(-\infty ;-1\right)\cup \left(0;+\infty \right)$

A. - 4

B. - 5

C. - 3

D. -2

A. $\frac{1}{2}$

B. $\frac{1}{3}$

C.1

D.2.

A. $x=\frac{1}{8}$

B. $x=\frac{1}{2}$

C. $x=\frac{1}{64}$

D. $x=\frac{1}{4}$