Bài tập Phép chia các phân thức đại số (có lời giải chi tiết)

A. $\frac{5}{3x^{2}y}$

B. $\frac{-5}{x^{2}y}$

C. $\frac{25}{3x^{2}y}$

D. $\frac{-25}{3x^{2}y}$

A. $\frac{4}{x+4}$

B. $-\frac{4}{x+4}$

C. $\frac{4}{3\left(x+4\right)}$

D. $-\frac{4}{3\left(x+4\right)}$

A. $\frac{(x-5)(3x-7)}{2}$

B . $\frac{(x+5)(3x-7)}{2}$

C. $\frac{x-5}{2}$

D. $\frac{3x-7}{2}$

A. $\frac{x}{3(x-1)}$

B. $-\frac{x}{3(x-1)}$

C. $\frac{x}{3(x+1)}$

D. $-\frac{x}{3(x+1)}$

A. $\frac{2-x}{x^2}$

B. $\frac{x-2}{x^2}$

C. $\frac{x+2}{x^2}$

D. $-\frac{x+2}{x^2}$

A. $\frac{x+3}{x+4}$

B. $\frac{1}{x+4}$

C. $\frac{x-3}{x+4}$

D . $\frac{x+3}{x-4}$

A. $\frac{x+3y}{4}$

B. $4\left(x+3y\right)$

C. $4\left(x-3y\right)$

D. $\frac{x-3y}{4}$

A. $\frac{4}{x-y}$

B. $\frac{4x}{x-y}$

C. $4{\left(x+y\right)}^2$

D. $4{\left(x-y\right)}^2$

A. $\frac{3(3x+y)}{2(3x-y)}$

B. $\frac{3{(3x+y)}^2}{2}$

C. $\frac{3{(3x-y)}^2}{2}$

D. $\frac{3}{2{(3x+y)}^2}$

A. $\frac{2(3x-y{)}^2}{3(x+y)}$

B. $\frac{-2\left(3x+y\right)(3x-y{)}^2}{3{(x+y)}^2}$

C. $\frac{-2{\left(3x+y\right)}^2(3x-y)}{3{(x+y)}^2}$

D. $\frac{2\left(3x+y\right)(3x-y{)}^2}{3(x+y)}$

A. $\frac{{(x-y)}^2}{{(x+y)}^2}:\frac{{(x-y)}^4}{{(x+y)}^3}$

B. $\frac{{(x-y)}^2}{{(x+y)}^2}:\frac{{(x-y)}^3}{{(x+y)}^3}$

C. $\frac{x-y}{{(x+y)}^2}:\frac{{(x-y)}^4}{{(x+y)}^3}$

D. $\frac{-{(x-y)}^2}{{(x+y)}^2}:\frac{{(x-y)}^4}{{(x+y)}^3}$

A. $\frac{5x^2-20y^2}{3x+6y}:\frac{5x-10y}{9x}$

B. $\frac{45x-90y}{3x+6y}:\frac{x^2-4y^2}{x^2+4xy+4y^2}$

C. $\frac{x^2-y^2}{2y}:(y-x)$

D. Cả A, B, C đều sai

A. x – 2; x + 2

B. ${(x–2)}^2$ ; x+ 2

C. x +2; ${(x–2)}^2$

D. $–{(x–2)}^2$ ; x+ 2

A. 6x; $x^2+4$

B. x; 5( $x^2+4$ )

C. 6x; 5( $x^2+4$ )

D. 3x; $x^2+4$

A. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=xy$

B. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=yz$

C. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=xyz$

D. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=1$

A. 1

B. 2

C. 3

D. 4