Trắc nghiệm Tổng và hiệu của hai vecto có đáp án

A. $\sqrt{5}$

B. $5\sqrt{5}$

C. 25

D. 5

A. $\sqrt{5}$

B. 15

C. 5

D. 2

A. $\stackrel{\to }{NC}+\stackrel{\to }{MC}và\stackrel{\to }{AD}$

B. $\stackrel{\to }{AM}+\stackrel{\to }{CD}và\stackrel{\to }{ND}$

C. $\stackrel{\to }{AB}-\stackrel{\to }{NC}và\stackrel{\to }{MB}$

D. $\stackrel{\to }{AM}+\stackrel{\to }{AN}và\stackrel{\to }{AB}+\stackrel{\to }{AD}$

A. $\stackrel{\to }{MN}+\stackrel{\to }{MP}+\stackrel{\to }{MC}=\stackrel{\to }{0}$

B. $\stackrel{\to }{PM}+\stackrel{\to }{PN}=\stackrel{\to }{AM}+\stackrel{\to }{AN}$

C. $\stackrel{\to }{AM}+\stackrel{\to }{AN}-\stackrel{\to }{AP}=\stackrel{\to }{0}$

D. $\stackrel{\to }{AM}+\stackrel{\to }{AN}+\stackrel{\to }{MN}=\stackrel{\to }{0}$

A. $\stackrel{\to }{AM}+\stackrel{\to }{BP}+\stackrel{\to }{CN}$

B. $\stackrel{\to }{BM}+\stackrel{\to }{AN}+\stackrel{\to }{CP}$

C. $\stackrel{\to }{AM}+\stackrel{\to }{BM}+\stackrel{\to }{CM}$

D. $\stackrel{\to }{AM}+\stackrel{\to }{AN}-\stackrel{\to }{AP}$

A. $\stackrel{\to }{AH}$

B. $\stackrel{\to }{AB}-\stackrel{\to }{AC}$

C. $\stackrel{\to }{AB}+\stackrel{\to }{AC}$

D. $\stackrel{\to }{AB}+\stackrel{\to }{AC}-\stackrel{\to }{AH}$

A. Tia phân giác của góc A

B. Đường cao hạ từ đỉnh A của tam giác ABC

C. Đường trung tuyến qua A của tam giác ABC

D. Đường thẳng BC

A. $\left(\stackrel{\to }{AB}+\stackrel{\to }{AC}\right)=\left(\stackrel{\to }{AB}-\stackrel{\to }{AC}\right)$

B. $\stackrel{\to }{AB}+\stackrel{\to }{AC}=\stackrel{\to }{AB}-\stackrel{\to }{AC}$

C. $\left(\stackrel{\to }{AB}\right)+\left(\stackrel{\to }{AC}\right)=\left(\stackrel{\to }{AB}+\stackrel{\to }{AC}\right)$

D. $\left(\stackrel{\to }{AB}\right)-\left(\stackrel{\to }{AC}\right)=\left(\stackrel{\to }{AB}-\stackrel{\to }{AC}\right)$

A. $\stackrel{\to }{AB}+\stackrel{\to }{AC}=\stackrel{\to }{BC}$

B. $\stackrel{\to }{AB}+\stackrel{\to }{CA}=\stackrel{\to }{CB}$

C. $\stackrel{\to }{CA}-\stackrel{\to }{BA}=\stackrel{\to }{BC}$

D. $\stackrel{\to }{AB}-\stackrel{\to }{BC}=\stackrel{\to }{CA}$

A. OA = OB

B. $\stackrel{\to }{OA}=\stackrel{\to }{OB}$

C. $\stackrel{\to }{AO}=\stackrel{\to }{BO}$

D. $\stackrel{\to }{OA}=-\stackrel{\to }{OB}$

A. $\stackrel{\to }{OA}-\stackrel{\to }{OB}=\stackrel{\to }{BA}$

B. $\stackrel{\to }{AB}-\stackrel{\to }{CB}=\stackrel{\to }{DB}$

C. $\stackrel{\to }{DA}-\stackrel{\to }{DB}=\stackrel{\to }{OD}+\stackrel{\to }{OC}$

D. $\stackrel{\to }{DA}-\stackrel{\to }{DB}+\stackrel{\to }{CD}=\stackrel{\to }{0}$

A. $\stackrel{\to }{OC}+\stackrel{\to }{OB}$

B. $\stackrel{\to }{BA}$

C. $\stackrel{\to }{OC}+\stackrel{\to }{OD}$

D. $\stackrel{\to }{CD}$

A. $\stackrel{\to }{AB}=\stackrel{\to }{AC}$

B. $\stackrel{\to }{AC}=a$

C. $\left(\stackrel{\to }{AC}\right)=\stackrel{\to }{CB}$

D. $\left(\stackrel{\to }{AB}+\stackrel{\to }{AC}\right)=a\sqrt{3}$

A. $\stackrel{\to }{AB}-\stackrel{\to }{IA}=\stackrel{\to }{BI}$

B. $\stackrel{\to }{BA}+\stackrel{\to }{BC}+\stackrel{\to }{DB}=\stackrel{\to }{0}$

C. $\stackrel{\to }{AB}-\stackrel{\to }{CD}=\stackrel{\to }{0}$

D. $\stackrel{\to }{AC}-\stackrel{\to }{BD}=\stackrel{\to }{0}$

A. $\stackrel{\to }{u}=\stackrel{\to }{AD}$

B. $\stackrel{\to }{u}=\stackrel{\to }{0}$

C. $\stackrel{\to }{u}=\stackrel{\to }{CD}$

D. $\stackrel{\to }{u}=\stackrel{\to }{AC}$

A. 4

B. 5

C. 10

D. 8

A. 9a

B. 3a

C. – 3a

D. 0

A. $\frac{a\sqrt{3}}{3}$

B. $a\sqrt{5}$

C. $\frac{a\sqrt{3}}{2}$

D. $\frac{a\sqrt{5}}{2}$

A. AA’

B. BB’

C. CC’

D. AA’ + BB’ + CC’

A. $\stackrel{\to }{a}=-\stackrel{\to }{b}$

B. $\stackrel{\to }{a}=\stackrel{\to }{b}$

C. $\stackrel{\to }{\left(a\right)}=\left(\stackrel{\to }{b}\right)$

D. $\left(\stackrel{\to }{a}\right)=\left(\stackrel{\to }{b}\right)=0$

A. $\left(\stackrel{\to }{AB}+\stackrel{\to }{AD}\right)=\left(\stackrel{\to }{CB}-\stackrel{\to }{CD}\right)$

B. $\stackrel{\to }{AB}+\stackrel{\to }{AD}=\stackrel{\to }{CB}-\stackrel{\to }{CD}$

C. $\stackrel{\to }{AB}+\stackrel{\to }{BD}=\stackrel{\to }{CB}+\stackrel{\to }{CD}$

D. $\stackrel{\to }{AC}+\stackrel{\to }{AD}=\stackrel{\to }{CD}$

A. 2a

B. $a\sqrt{2}$

C. 0

D. $2a\sqrt{2}$

A. $\stackrel{\to }{AB}+\stackrel{\to }{DC}=\stackrel{\to }{AC}+\stackrel{\to }{BD}$

B. $\stackrel{\to }{AB}+\stackrel{\to }{BC}=\stackrel{\to }{AC}+\stackrel{\to }{DB}$

C. $\stackrel{\to }{AD}+\stackrel{\to }{BE}+\stackrel{\to }{CF}=\stackrel{\to }{AE}+\stackrel{\to }{BF}+\stackrel{\to }{CD}$

D. $\stackrel{\to }{AB}=\stackrel{\to }{DC}$

A. $\left(\stackrel{\to }{AB}+\stackrel{\to }{CD}\right)=0$

B. $\left(\stackrel{\to }{AB}+\stackrel{\to }{CD}\right)=\left(\stackrel{\to }{AB}-\stackrel{\to }{CD}\right)$

C. $\stackrel{\to }{AB}+\stackrel{\to }{CD}=\stackrel{\to }{AB}-\stackrel{\to }{CD}$

D. $\left(\stackrel{\to }{AB}-\stackrel{\to }{CD}\right)=0$