Trắc nghiệm Lũy thừa có đáp án (Thông hiểu)

A. ${\left(\frac{5}{4}\right)}^m>{\left(\frac{6}{5}\right)}^m>1$

B. ${\left(\frac{5}{4}\right)}^m<{\left(\frac{6}{5}\right)}^m<1$

C. ${\left(\frac{5}{4}\right)}^m<1<{\left(\frac{6}{5}\right)}^m$

D. $1<{\left(\frac{5}{4}\right)}^m<{\left(\frac{6}{5}\right)}^m$

A. 0

B. 1

C. 2

D. vô số

A. ${\left(\frac{3}{4}\right)}^m>{\left(\frac{1}{2}\right)}^m$

B. $1<{\left(\frac{4}{3}\right)}^m$

C. ${\left(\frac{2}{3}\right)}^m<{\left(\frac{3}{4}\right)}^m$

D. ${\left(\frac{13}{7}\right)}^m>2^m$

A. b,c,a

B. c,a,b

C. c,b,a

D. b,a,c

A. ${\left(2-\sqrt{2}\right)}^3<{\left(2-\sqrt{2}\right)}^4$

B. ${\left(4-\sqrt{2}\right)}^3<{\left(4-\sqrt{2}\right)}^4$

C. ${\left(\sqrt{11}-\sqrt{2}\right)}^6>{\left(\sqrt{11}-\sqrt{2}\right)}^7$

D. ${\left(\sqrt{3}-\sqrt{2}\right)}^4<{\left(\sqrt{3}-\sqrt{2}\right)}^5$

A. m < n

B. m > n

C. $m\le n$

D. m = n

A. m < n

B. m > n

C. $m\le n$

D. m = n

A. $P=2\sqrt{6}-5$

B. $P={\left(2\sqrt{6}-5\right)}^{2020}$

C. $P={\left(2\sqrt{6}+5\right)}^{2020}$

D. $P=2\sqrt{6}+5$

A. $a^n$

B. $b^n$

C. $a^{\alpha }$

D. $b^{\alpha }$

A. ${\left(1-\sqrt{2}\right)}^{-3}$

B. ${\left(2-\sqrt{2}\right)}^0$

C. ${\left(3-2\sqrt{2}\right)}^{3-2\sqrt{2}}$

D. ${\left(-\frac{3}{2}\right)}^{\pi }$

A. ${\left(-3\right)}^{-4}$

B. ${\left(-3\right)}^{-\frac{1}{3}}$

C. $0^4$

D. ${\left(\frac{1}{2^{-3}}\right)}^0$

A. ${\left(2^x\right)}^y=2^{x+y}$

B. $\frac{2^x}{2^y}=2^{\frac{x}{y}}$

C. $2^x{.2}^y=2^{x+y}$

D. ${\left(\frac{2}{3}\right)}^x=\frac{2^x}{3^y}$

A. $a^{\frac{1}{n}}=\sqrt[n]{a},\forall a\ne 0$

B. $a^{\frac{1}{n}}=\sqrt[n]{a},\forall a>0$

C. $a^{\frac{1}{n}}=\sqrt[n]{a},\forall a>0$

D. $a^{\frac{1}{n}}=\sqrt[n]{a},\forall a\in R$

A. $3^{x+y}=3^x+3^y$

B. $2^x-2^y=2^{\frac{x}{y}}$

C. ${\pi }^{xy}={\left({\pi }^x\right)}^y$

D. ${\left(\frac{\pi }{2}\right)}^x=\frac{{\pi }^x}{2^y}$

A. $\sqrt{ab}=\sqrt{a}\sqrt{b,}\forall a,b$

B. $\sqrt[2n]{a^{2n}}\ge 0\forall a,n$ nguyên dương $n\ge 2$

C. $\sqrt[2n]{a^{2n}}=\left(a\right)\forall a,n$ nguyên dương $n\ge 2$

D. $\sqrt[4]{a^2}=\sqrt{a}\forall a\ge 0$

A. $2^{\sqrt{x}}=x^{\sqrt{2}}$

B. $3^{\sqrt{xy}}={\left(3^{\sqrt{x}}\right)}^{\sqrt{y}}$

C. $\frac{3^{\sqrt[3]{x}}}{3^{\sqrt[3]{y}}}=3^{\sqrt[3]{x-y}}$

D. $x^{\sqrt{3}}=y^{\sqrt{3}}$

A. ${\pi }^x=x^{\pi }$

B. $3^{\sqrt{xy}}=3^{\sqrt{x}}{.3}^{\sqrt{y}}$

C. ${\left(\frac{1}{2}\right)}^{x-y}=2^{y-x}$

D. ${\left(x-y\right)}^3={\left(y-x\right)}^3$

A. $\sqrt[4]{a^4{b}^4}=ab$

B. $\sqrt[3]{a^3{b}^3}=ab$

C. $\sqrt{a^2{b}^2}=\left(ab\right)$

D. $\sqrt{a^2{b}^4}=a{b}^2$

A. 25

B. 15

C. 9

D. 5

A. a > 1

B. 0 < a < 1

C. 1 < a < 2

D. a < 1