Trắc nghiệm Các định nghĩa có đáp án (Vận dụng)

A. $\stackrel{\rightharpoonup }{OF},\stackrel{\rightharpoonup }{DE},\stackrel{\rightharpoonup }{OC}$

B. $\stackrel{\rightharpoonup }{CA},\stackrel{\rightharpoonup }{OF},\stackrel{\rightharpoonup }{DE}$

C. $\stackrel{\rightharpoonup }{OF},\stackrel{\rightharpoonup }{DE},\stackrel{\rightharpoonup }{CO}$

D. $\stackrel{\rightharpoonup }{OF},\stackrel{\rightharpoonup }{ED},\stackrel{\rightharpoonup }{OC}$

A. 4

B. 6

C. 7

D. 9

A. $\stackrel{\rightharpoonup }{MN}=\stackrel{\rightharpoonup }{QP}$

B. $\stackrel{\rightharpoonup }{MQ}=\stackrel{\rightharpoonup }{NP}$

C. $\left(\stackrel{\rightharpoonup }{PQ}\right)=\left(\stackrel{\rightharpoonup }{MN}\right)$

D. $\left(\stackrel{\rightharpoonup }{MN}\right)=\left(\stackrel{\rightharpoonup }{AC}\right)$

A. $\stackrel{\rightharpoonup }{MN}=\stackrel{\rightharpoonup }{QP}$

B. $\left(\stackrel{\rightharpoonup }{QP}\right)=\left(\stackrel{\rightharpoonup }{MN}\right)$

C. $\stackrel{\rightharpoonup }{MQ}=\stackrel{\rightharpoonup }{NP}$

D. $\left(\stackrel{\rightharpoonup }{MN}\right)=\left(\stackrel{\rightharpoonup }{AC}\right)$

A. $\stackrel{\rightharpoonup }{OA},\stackrel{\rightharpoonup }{DO},\stackrel{\rightharpoonup }{EF},\stackrel{\rightharpoonup }{CB}$

B. $\stackrel{\rightharpoonup }{OA},\stackrel{\rightharpoonup }{DO},\stackrel{\rightharpoonup }{EF}\stackrel{\rightharpoonup }{,OB},\stackrel{\rightharpoonup }{DA}$

C. $\stackrel{\rightharpoonup }{OA},\stackrel{\rightharpoonup }{DO},\stackrel{\rightharpoonup }{EF},\stackrel{\rightharpoonup }{CB},\stackrel{\rightharpoonup }{DA}$

D. $\stackrel{\rightharpoonup }{DO},\stackrel{\rightharpoonup }{EF},\stackrel{\rightharpoonup }{CB},\stackrel{\rightharpoonup }{BC}$

A. $\stackrel{\rightharpoonup }{AB}=\stackrel{\rightharpoonup }{ED}$

B. $\left(\stackrel{\rightharpoonup }{AB}\right)=\left(\stackrel{\rightharpoonup }{AF}\right)$

C. $\stackrel{\rightharpoonup }{OD}=\stackrel{\rightharpoonup }{BC}$

D. $\stackrel{\rightharpoonup }{OB}=\stackrel{\rightharpoonup }{OE}$

A. $\stackrel{\rightharpoonup }{HB}=\stackrel{\rightharpoonup }{HC}$

B. $\left(\stackrel{\rightharpoonup }{AC}\right)=2\left(\stackrel{\rightharpoonup }{HC}\right)$

C. $\left(\stackrel{\rightharpoonup }{AH}\right)=\frac{\sqrt{3}}{2}\left(\stackrel{\rightharpoonup }{HC}\right)$

D. $\stackrel{\rightharpoonup }{AB}=\stackrel{\rightharpoonup }{AC}$

A. $\left(\stackrel{\rightharpoonup }{HB}\right)=\frac{a}{2}$

B. $\left(\stackrel{\rightharpoonup }{AH}\right)=\frac{a\sqrt{3}}{2}$

C. $\left(\stackrel{\rightharpoonup }{CH}\right)=\frac{a\sqrt{3}}{2}$

D. $\left(\stackrel{\rightharpoonup }{BH}\right)=\left(\stackrel{\rightharpoonup }{HC}\right)$

A. $\stackrel{\rightharpoonup }{HA}=\stackrel{\rightharpoonup }{CD}$ và $\stackrel{\rightharpoonup }{AD}=\stackrel{\rightharpoonup }{CH}$

B. $\stackrel{\rightharpoonup }{HA}=\stackrel{\rightharpoonup }{CD}$ và $\stackrel{\rightharpoonup }{DA}=\stackrel{\rightharpoonup }{HC}$

C. $\stackrel{\rightharpoonup }{HA}=\stackrel{\rightharpoonup }{CD}$ và $\stackrel{\rightharpoonup }{AD}=\stackrel{\rightharpoonup }{HC}$

D. $\stackrel{\rightharpoonup }{HA}=\stackrel{\rightharpoonup }{CD}$ và $\stackrel{\rightharpoonup }{AD}=\stackrel{\rightharpoonup }{HC}$ và $\stackrel{\rightharpoonup }{OB}=\stackrel{\rightharpoonup }{OD}$

A. 0

B. 1

C. 2

D. Vô số

A. $\stackrel{\to }{AB}=\stackrel{\to }{AD}$

B. $\left(\stackrel{\to }{BD}\right)=a$

C. $\stackrel{\to }{BD}=\stackrel{\to }{AC}$

D. $\stackrel{\to }{BC}=\stackrel{\to }{DA}$